Let A be the set of first 10 natural numbers and R be a relation on A defined by x - y - R - x -2 y -10- Then the range of R isA- 1-2-3- - 10B- 2-4-6-8C- 2-4-6-8-10D- 1-2-3-4

The correct option is D {1,2,3,4}y=10 x2 y ∈ℕ⇒ x should be even number. So, Domain = {2,4,6,8} ⇒ Range ={4,3,2,1} ...

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Range

Let A be the ...

Question

Let $A$ be the set of first $10$ natural numbers and $R$ be a relation on $A$ defined by $(x, y) \in R \Leftrightarrow x + 2 y = 10.$ Then the range of $R$ is

{1, 2, 3, \dots, 10}

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{2, 4, 6, 8}

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{2, 4, 6, 8, 10}

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{1, 2, 3, 4}

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Solution

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A

10

R

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(x, y) \in R \Leftrightarrow x + 2 y = 10.

R

A

R

A \times A

R = {(x, y) : x + 2 y = 10; x, y \in A} .

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(x, y) \in R^{'}

x + 2 y = 10

R = {(x, y); x \in A, y \in A and x + 2 y = 10}

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R^{- 1}

R^{- 1}

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