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Question

Let a be the solution of the equation 4x212x+9=16, then the value of 10a15 is

A
20
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B
25
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C
30
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D
35
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Solution

The correct option is A 20
4x212x+9=16
4x212x7=0
x=12±144+1128
x=12±168
x=0.5,3.5
Substituting the value of a in 10a15, we get 3515=20 and 515=10

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