LetA=[0α00] and (A+I)50−50A=[abcd],Then, the value of a+b+c+d is
2
1
4
none of these
As A2=O, Ak=O ∀ k ≥ 2Thus, (A+I)50=I+50A⇒(A+I)50−50A=I+50A−50A=I⇒a=1, b=0, c=0, d=1a+b+c+d=2
Let A=[1234] and B=[abcd] are two matrices such that AB = BA and c≠0, then value of a−d3b−c is :