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Question

Let A=111213111 and 10B=42250α123. If B is the inverse of matrix A, then α is

A
2
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B
1
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C
2
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D
5
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Solution

The correct option is D 5
Since, B is the inverse of matrix A.
So, 10A1=42250α123
10A1A=42250α123111213111
10I=4+4+24+2+246+25+0+α5+0+α5+0+α14+312+31+6+3
100001000010=10005+α5+α5+α0010
5+α=0
α=5

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