Let A=⎡⎢⎣1−1121−3111⎤⎥⎦ and 10B=⎡⎢⎣422−50α1−23⎤⎥⎦. If B is the inverse of matrix A, then α is
A
−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D5 Since, B is the inverse of matrix A. So, 10A−1=⎡⎢⎣422−50α1−23⎤⎥⎦ ⇒10A−1⋅A=⎡⎢⎣422−50α1−23⎤⎥⎦⎡⎢⎣1−1121−3111⎤⎥⎦ ⇒10I=⎡⎢⎣4+4+2−4+2+24−6+2−5+0+α5+0+α−5+0+α1−4+3−1−2+31+6+3⎤⎥⎦ ⇒⎡⎢⎣100001000010⎤⎥⎦=⎡⎢⎣1000−5+α5+α−5+α0010⎤⎥⎦ ⇒−5+α=0 ⇒α=5