Let A - begin bmatrix 182 13 - 4end bmatrix and B- begin bmatrix a - k 1C - d lend bmatrix are two matrices such that AB - BA and -0- then value of a - d -3 b - c is -A- -1B- 2C- 0D- -2

Let $A = [\begin{matrix} 1 & 2 3 & 4 \end{matrix}]$ and $B = [\begin{matrix} a & b c & d \end{matrix}]$ are two matrices such that AB = BA and $c \neq 0$ , then value of $\frac{a - d}{3 b - c}$ is :

Let $A = [\begin{matrix} 1 & 2 3 & 4 \end{matrix}]$ and $B = A = [\begin{matrix} a & b c & d \end{matrix}]$ are two matrices such that AB = BA and $c \neq 0$ , then value of $\frac{a - d}{3 b - c}$ is :

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Let A=[1234] and B=[abcd] are two matrices such that AB = BA and c≠0, then value of a−d3b−c is :

The correct option is C -1AB=[1234][abcd]=[a+2cb+2d3a+4c3b+4d]BA=[abcd][1234]=[a+3b2a+4bc+3d2c+4d] If AB = BA, then a + 2c = a + 3b ⇒ 2c = 3b ⇒b≠0 b + 2d = 2a + 4b ⇒ 2a - 2d = -3b a−d3b−c=−32b3b−32b=−1

Let $A = [\begin{matrix} 1 & 2 3 & 4 \end{matrix}]$ and $B = [\begin{matrix} a & b c & d \end{matrix}]$ are two matrices such that AB = BA and $c \neq 0$ , then value of $\frac{a - d}{3 b - c}$ is :