wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Let A=207010121 and α14α7α010α4α2α. If AB=I, where I is an identity matrix of order 3 then trace B has value equal to

A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0
x=0.47777
100x=47.777
10x=4.77790x=43
x=4390



x=0.001
x=0.001001001
100x=.100100100
100000x=100.10010099900x=99
x=9999900
x=1111100


A=207010121
B=α14α7α010α4α2α
AB=2α+07α0+0+02α+02α0+0+00+1+08α009α
α=19
trace (B)=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Matrices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon