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Question

Let A=[2102],B=[4132] and C=[3214]
Find: A2+AC5B

A
[1001]
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B
[233176]
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C
[233176]
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D
[233176]
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Solution

The correct option is D [233176]
A2=[2102][2102][2×2+1×02×1+1×20×2+2×00×1+(2)(2)]
=[4004]
AC=[2102][3214]
=[3×2+1×12×2+1×40×3+(2)×(1)0×2+(2×4)]
=[7828]
5B=[2051510]
A2+AC5B=[400+4]+[7828][2051510]
=[233176]

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