Let- A - begin bmatrix 4 - 6 -138082111 -2 - 5 1lend bmatrix - - B - bmatrix 2 - 4110 - 111-1 - 2 lendbmatrix and C- 1 2 3 -The expression which is not defined is-A- CABB- A-B-C- A2-AD- B - B

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Byju's Answer

Standard XII

Mathematics

Multiplication of Matrices

Let, A = begi...

Question

Let,
$A = ⎡ ⎢ ⎣ \begin{matrix} 4 & 6 & - 1 3 & 0 & 2 1 & - 2 & 5 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 & 4 0 & 1 - 1 & 2 \end{matrix} ⎤ ⎥ ⎦$
$and C = [\begin{matrix} 1 & 2 & 3 \end{matrix}]$
The expression which is not defined is:

B^{'} B

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C A B

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A + B^{'}

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A^{2} + A

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Solution

The correct option is C $A + B^{'}$
We can see from the options that if we take transpose of B,
$B^{'}$ will be of 2 x 3 matrix which cannot be added to a 3 x 3 matrix, as for the addition the order should be the same.

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Similar questions

Let $A = ⎡ ⎢ ⎣ \begin{matrix} 4 & 6 & - 1 3 & 0 & 2 1 & - 2 & 5 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 & 4 0 & 1 - 1 & 2 \end{matrix} ⎤ ⎥ ⎦$ and C = [3 1 2]. The expression which is not defined is

Q. Let

A = ⎡ ⎢ ⎣ \begin{matrix} 4 & 6 & - 1 3 & 0 & 2 1 & - 2 & 5 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 & 4 0 & 1 - 1 & 2 \end{matrix} ⎤ ⎥ ⎦

and C = [3 1 2]. The expression which is not defined is

Q. Let

A = ⎡ ⎢ ⎣ \begin{matrix} 4 & 6 & - 1 3 & 0 & 2 1 & - 2 & 5 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 & 4 0 & 1 - 1 & 2 \end{matrix} ⎤ ⎥ ⎦

and C = [3 1 2]. The expression which is not defined is

Q. Let,

A = ⎡ ⎢ ⎣ \begin{matrix} 4 & 6 & - 1 3 & 0 & 2 1 & - 2 & 5 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 & 4 0 & 1 - 1 & 2 \end{matrix} ⎤ ⎥ ⎦

and C = [\begin{matrix} 1 & 2 & 3 \end{matrix}]

The expression which is not defined is:

Let $A = [\begin{matrix} 2 & 1 0 & - 2 \end{matrix}], B = [\begin{matrix} 4 & 1 - 3 & - 2 \end{matrix}]$ and $C = [\begin{matrix} - 3 & 2 - 1 & 4 \end{matrix}]$ Find: $A^{2} + A C - 5 B$

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Let, A=⎡⎢⎣46−13021−25⎤⎥⎦, B=⎡⎢⎣2401−12⎤⎥⎦ and C=[123] The expression which is not defined is:

The correct option is C A+B′We can see from the options that if we take transpose of B, B′ will be of 2 x 3 matrix which cannot be added to a 3 x 3 matrix, as for the addition the order should be the same.

Let,
$A = ⎡ ⎢ ⎣ \begin{matrix} 4 & 6 & - 1 3 & 0 & 2 1 & - 2 & 5 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 & 4 0 & 1 - 1 & 2 \end{matrix} ⎤ ⎥ ⎦$
$and C = [\begin{matrix} 1 & 2 & 3 \end{matrix}]$
The expression which is not defined is:

The correct option is C $A + B^{'}$
We can see from the options that if we take transpose of B,
$B^{'}$ will be of 2 x 3 matrix which cannot be added to a 3 x 3 matrix, as for the addition the order should be the same.