Given ,A3=0
⇒|A|3=0
⇒|A|=0
⇒ad−bc=0 ....(1)
Now, A2=[abcd][abcd]
⇒A2=[a2+bcab+bdac+dcbc+d2]
=[a2+adab+bdac+dcad+d2] (by (1))
=[a(a+d)b(a+d)(a+d)cd(a+d)]
=(a+d)[abcd]
⇒A2=(a+d)A .....(2)
Now, since, A3=O
A2A=O
(a+d)AA=O
⇒(a+d)2A=O
⇒a+d=0 (∵ A is not a zero matrix)
Hence, from (2), we get
A2=O