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Question

Let A=[x+yy2xxy],B=[21] and C=[32]. If AB=C, then find x and y

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Solution

Given:A=[x+yy2xxy]
B=[21]
AB=[x+yy2xxy].[21]
=[2x+2yy4xx+y]
=[2x+y3x+y]
Given AB=C
[2x+y3x+y]=[32]
2x+y=3 and 3x+y=2
3x+y2xy=23
x=1
put x=1 in 2x+y=3 we get
2×1+y=3
y=3+2=5
x=1,y=5


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