Let a circle C touch the lines L1:4x−3y+K1=0 and L2:4x−3y+K2=0,K1,K2∈R. If a line passing through the centre of the circle C intersects L1 at (−1,2) and L2 at (3,−6), then the equation of the circle C is:
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Solution
Co-ordinate of centre C≡(3+(−1)2,−6+22)≡(1,−2) L1 is passing through A ⇒−4−6+K1=0 ⇒K1=10 L2 is passing through B ⇒12+18+K2=0 ⇒K2=−30
Equation of L1:4x−3y+10=0
Equation of L2:4x−3y−30=0
Diameter of circle =∣∣
∣
∣∣10+30√42+(−3)2∣∣
∣
∣∣=8 ⇒ Radius =4
Equation of circle (x−1)2+(y+2)2=16