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Question

Let a circle C touch the lines L1:4x3y+K1=0 and L2:4x3y+K2=0,K1,K2R. If a line passing through the centre of the circle C intersects L1 at (1,2) and L2 at (3,6), then the equation of the circle C is:

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Solution


Co-ordinate of centre C(3+(1)2,6+22)(1,2)
L1 is passing through A
46+K1=0
K1=10
L2 is passing through B
12+18+K2=0
K2=30
Equation of L1:4x3y+10=0
Equation of L2:4x3y30=0
Diameter of circle =∣ ∣ ∣10+3042+(3)2∣ ∣ ∣=8
Radius =4
Equation of circle (x1)2+(y+2)2=16

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