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Byju's Answer
Standard XII
Mathematics
Integration by Substitution
Let a=cosα+...
Question
Let
a
=
cos
α
+
i
sin
α
then prove that
a
n
+
1
a
n
=
2
cos
n
α
for
n
being natural number.
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Solution
Given,
a
=
cos
α
+
i
sin
α
.
Now,
a
n
=
cos
n
α
+
i
sin
n
α
[ Using De Moivre's theorem] [ for
n
being natural number]
Then
1
a
n
=
a
−
n
=
cos
n
α
−
sin
n
α
.
[ Using De Moivre's theorem]
So
a
n
+
1
a
n
=
(
cos
n
α
+
i
sin
n
α
)
+
(
cos
n
α
−
i
sin
n
α
)
=
2
cos
n
α
.
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