Let A - 2-3e - i-6- 2-3e i-2- 2-3e - i5-6 three points forming a triangle ABC in the plane then triangle ABC is

The correct option is A Equilateral arg(A)= π #160; 6 arg(B)= π #160; 2 arg(C)= 5π #160; 6 arg(A) arg(B)= 2π #160; 3 arg( ...

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Cosine Rule

Let A = 2√3e...

Question

Let A = $\frac{2}{\sqrt{3}} e^{- i \frac{π}{6}}$ , $\frac{2}{\sqrt{3}} e^{i \frac{π}{2}}$ , $\frac{2}{\sqrt{3}} e^{- i \frac{5 π}{6}}$ three points forming a triangle ABC in the plane then triangle ABC is

Equilateral

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Isosceles

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Scalene

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Right angled

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Solution

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Similar questions

A = \frac{2}{\sqrt{3}} e^{- i \frac{π}{6}}

B = \frac{2}{\sqrt{3}} e^{i \frac{π}{2}}

C = \frac{2}{\sqrt{3}} e^{- \frac{i 5 π}{6}}

A = \frac{2}{\sqrt{3}} e^{- i \frac{π}{6}}, B = \frac{2}{\sqrt{3}} e^{i \frac{π}{2}}, C = \frac{2}{\sqrt{3}} e^{- \frac{5 π}{6}}

A = \frac{2}{3} e^{\frac{i π}{2}}, B = \frac{2}{3} e^{\frac{i π}{6}}, C = \frac{2}{3} e^{\frac{i 5 π}{6}}

△ A B C

△ A B C

A (\frac{2}{\sqrt{3}} e^{i π / 2}), B (\frac{2}{\sqrt{3}} e^{- i π / 6})

C (\frac{2}{\sqrt{3}} e^{- i 5 π / 6}) .

P

A P^{2} + B P^{2} + C P^{2} =

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