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Question

Let a force F be acting on a body free to rotate about a point O and let r be the position vector of any point P on the line of action of the force. Then torque τ of this force about point O is defined as :
τ=r×F
Given, F=(2^i+3^j^k) N and r=(^i^j+6^k) m. Find the torque of this force.

A
(17^i+13^j+5^k) Nm
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B
(17^i+13^j+5^k) Nm
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C
(17^i13^j+5^k) Nm
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D
(17^i+13^j+10^k) Nm
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Solution

The correct option is A (17^i+13^j+5^k) Nm
τ=r×F=^i^j^k116231
=^i(118)^j(112)+^k(3+2)
=(17^i+13^j+5^k)Nm

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