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Question

Let a=i−k,b=xi+j+(1−x)k and c=yi+xj+(1+x−y)k. Then, [abc] depends on

A
Neither x nor y
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B
Both x and y
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C
Only x
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D
Only y
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Solution

The correct option is A Neither x nor y
Given, a=ik,b=xi+j+(1x)k and c=yi+xj+(1+xy)k
Therefore, [abc]=∣ ∣101x11xyx1+xy∣ ∣
Applying C3C3+C1
=∣ ∣100x11yx1+x∣ ∣
=1[1+xx]=1
Thus, [abc] does not depend upon neither x nor y.

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