Let a=i−k,b=xi+j+(1−x)k and c=yi+xj+(1+x−y)k. Then, [abc] depends on
A
Neither x nor y
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B
Both x and y
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C
Only x
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D
Only y
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Solution
The correct option is A Neither x nor y Given, a=i−k,b=xi+j+(1−x)k and c=yi+xj+(1+x−y)k Therefore, [abc]=∣∣
∣∣10−1x11−xyx1+x−y∣∣
∣∣ Applying C3→C3+C1 =∣∣
∣∣100x11yx1+x∣∣
∣∣ =1[1+x−x]=1 Thus, [abc] does not depend upon neither x nor y.