The correct options are
A reflexive
B transitive
D symmetric
A={1,2,3}A × A ={(1,1),(1,2),(1,3),(2,1),(2,2),(2,3),(3,1),(3,2),(3,3)}.
R is reflexive since (a,a) ∈ R ∀a∈A.
R is symmetric since (a,b) ∈ R and (b,a) ∈ R, ∀a,b∈A.
R is transitive since(a,b), ∈ R,(b,c) ∈ R,(a,c) ∈ R, ∀a,b,c∈A.