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Question

Let A=3x216x,B=[a,b,c] and C=⎢ ⎢(x+2)25x22x5x22x(x+2)22x(x+2)25x2⎥ ⎥ be three given matrices, where a,b,c and xR, Given that tr.(AB)=tr.(C)xR, where tr.(A) denotes trace of A. Find the value of (a+b+c)

A
6
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B
7
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C
8
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D
9
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Solution

The correct option is C 7
Given A=3x216x,B=[a,b,c]
Here, AB=3x216x[a,b,c]
AB=3ax23bx23cx2abc6ax6bx6cx
tr(AB)=3ax2+b+6cx
Now, given C=⎢ ⎢(x+2)25x22x5x22x(x+2)22x(x+2)25x2⎥ ⎥
tr(C)=(x+2)2+2x+5x2
tr(C)=6x2+6x+4
Since, we have tr(AB)=tr(C)
3ax2+b+6cx=6x2+6x+4
On comparing, we get a=2,b=4,c=1
So, a+b+c=7

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