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Question

Let A={xR:x2|x|2=0} and B={α+β, αβ} where α,β are real roots of the quadratic equation x2+|x|2=0. If (a,b)A×B, then the quadratic equation whose roots are a,b is

A
x22x=0
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B
x2x2=0
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C
x2+2x=0
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D
x2+3x+2=0
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Solution

The correct option is D x2+3x+2=0
x2|x|2=0
|x|2|x|2=0
(|x|2)(|x|+1)=0
|x|=2
A={2,2}

x2+|x|2=0
(|x|1)(|x|+2)=0
x=±1
B={1,0}
Hence, A×B={(2,1),(2,0),(2,1),(2,0)}

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