Let A={(x,y):y2≤4x,y−2x⩾−4}. The area (in square units) of the region A is :
A
8
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B
9
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C
10
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D
11
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Solution
The correct option is B 9 Point of intersection of parabola and line are (1,-2) and (4,4) Required area =∫4−2(x1−x2)dy=∫4−2y24dy−∫4−212(y+4)dy =[y312]4−2−12[y22+4y]4−2 =6−15=−9 Area = 9 sq.units