Question

Let $A=\{x,y,z\}$ and $B=\{p,q,r,s\}$. What is the number of distinct relations from $B$ to $A$?

• A. $4096$
• B. $4094$
• C. $128$
• D. $126$

Answer 1

The correct option is A $4096$

Since, No. of elements in set A$=3$
No. of elements in set B$=4$
$\therefore$ No. of elements in B$\times$A$=3\times 4=12$
$\therefore$ No. of distinct relations from B to A $=2^{12}=4096$
Option A is correct.