Let a matrix A=[cosxsinxtanxcotx], then which of the following statement(s) is(are) true for atleast one value of x∈[0,π2] ?
(where Cij is co-factor of element [aij])
A
C11=1
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B
C12=1
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C
C21=1
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D
C22=1
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Solution
The correct option is DC22=1 Given : A=[cosxsinxtanxcotx] ⇒M11=cotx,M12=tanx,M21=sinx,M22=cosx and
we know, Cij=(−1)i+iMij
So, C11=cotx=1 at x=nπ+π4
For n=0,x∈[0,π2] C12=−tanx=1 at x=nπ−π4
No possible value for x∈[0,π2] C21=−sinx=1 at x=2nπ−π2
No possible value for x∈[0,π2] C22=cosx=1 at x=2nπ
For n=0,x∈[0,π2]
(where n=0,±1,±2,⋯)