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Question

Let an denote the number of all n-digit positive integers formed by the digits 0,1 or both such that no consecutive digits in them are 0. Let bn= the number of such n-digit integers ending with digit 1 and cn= the number of such n-digit integers ending with digit 0. The value of b6 is

A
7
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B
8
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C
9
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D
11
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Solution

The correct option is B 8
To find b6, we have to find all 6 digit numbers ending with '1' such that no consecutive digits are '0'. Some of the examples possible are :
1. 1 0 1 1 1 1
2. 1 0 1 0 1 1
3. 1 1 1 1 1 1
Three case possible:
1. One zero- It can be placed in any of the four places.
So, we get '4' such six digit numbers.
2. Two zeros- We get '3' such six digit numbers possible.
3. No zeros- We get only '1' such six digit number.
Hence b6=4+3+1=8

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