wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Let an denote the number of all n-digit positive integers formed by the digits 0,1 or both such that no consecutive digits in them are 0. Let bn= the number of such n-digit integers ending with digit 1 and cn= the number of such n-digit integers ending with digit 0. The value of b6 is

A
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 8
To find b6, we have to find all 6 digit numbers ending with '1' such that no consecutive digits are '0'. Some of the examples possible are :
1. 1 0 1 1 1 1
2. 1 0 1 0 1 1
3. 1 1 1 1 1 1
Three case possible:
1. One zero- It can be placed in any of the four places.
So, we get '4' such six digit numbers.
2. Two zeros- We get '3' such six digit numbers possible.
3. No zeros- We get only '1' such six digit number.
Hence b6=4+3+1=8

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon