Let an=n.2n+n2+n+1,bn=an+1−an,Cn=bn+1−bn,dn=Cn+1−Cn… and So on zn=yn+1−yn∀nϵN The value of n for which xn,yn,zn are in G.P is
Find the value of nC0.(n+1)+n.nC1+(n−1)nC2....1.nCn