Let a perpendicular PQ be drawn from P5- 7- 3 to the line x - 153 - y - 298 - z - 5-5 where Q is the foot of perpendicular- then

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Standard VIII

Mathematics

Line Graph

Let a perpend...

Question

Let a perpendicular $P Q$ be drawn from $P (5, 7, 3)$ to the line $\frac{x - 15}{3} = \frac{y - 29}{8} = \frac{z - 5}{- 5}$ where $Q$ is the foot of perpendicular, then

Q

(9, 13, 15)

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P Q = 14

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The equation of plane containing

P Q

and the given line is

9 x - 4 y - z - 14 = 0

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None of these

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Solution

The correct options are
A $Q$ is $(9, 13, 15)$
C The equation of plane containing $P Q$ and the given line is $9 x - 4 y - z - 14 = 0$

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Q. From the point

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Let a perpendicular PQ be drawn from P(5,7,3) to the line x−153=y−298=z−5−5 where Q is the foot of perpendicular, then

The correct options are A Q is (9,13,15) C The equation of plane containing PQ and the given line is 9x−4y−z−14=0

Let a perpendicular $P Q$ be drawn from $P (5, 7, 3)$ to the line $\frac{x - 15}{3} = \frac{y - 29}{8} = \frac{z - 5}{- 5}$ where $Q$ is the foot of perpendicular, then

The correct options are
A $Q$ is $(9, 13, 15)$
C The equation of plane containing $P Q$ and the given line is $9 x - 4 y - z - 14 = 0$