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Question

Let a pring with force constant k is compressed by x1. Stored potential energy of the spring U1 = 12 k x2 . Let it be further compressed by x2. Let it be further compressed by x2 . Change in potential energy of the spring


A

k ( - )

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B

k [ (() - )]

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C

k

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D

k

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Solution

The correct option is B

k [ (() - )]


ΔU = Uf - Ui

Uf=12K(x1+x2)2

Ui = 12K x12

Δ U= 12 K (x1+x2)2 - 12 k x12


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