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Question

Let A=Q×Q and let* be a binary operation on A defined by (a,b)(c,d)=(ac,b+ad)for(a,b),(c,d)ϵA. Determine, whether * is commutative and associative. Then, with respect to * on A
Find the invertible elements of A.

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Solution

(i) For any (a, b), (c, d) and (e, f)A, we have .
{(a,b)(c,d)}(e,f)
=(ac,b+ad)(e,f)
=(ace,b+ad+acf)
and
(a,b){cc,d)(e,f)}
=(a,b)(ce,d+cf)
=(ace,b+ad+acf)
So, {(a,b)(c,d)}(e,f)=(a,b){(c,d)(e,f)} for all a, b, c, d Q×Q=A
"" is associative on A.
(ii) Let (a, b) be invertible element on A
(c,d)A such that
(a,b)(c,d)=(1,0)=(c,d)(a,b)
(ac,b+ad)=(1,0) and (ca,d+bc)=(1,0)
ac=1,b+ad=0 and ca=1,d+bc=0
c=1a,d=ba if a0
Thus (a,b) is invertible element of A.

1233784_1502072_ans_656e8d53364b49aa9426c0ccb987a40c.jpg

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