Let a,r,s and t be non –zero real numbers. Let P(at2,2at),Q,R(ar2,2ar) and S(as2,2as) be distinct points on the parabola y2=4ax. Suppose that PQ is the focal chord and lines QR and PK are parallel, where K is point (2a,0). The value of r is
A
−1t
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B
t2+1t
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C
1t
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D
t2−1t
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Solution
The correct option is Dt2−1t (i) P(at2,2at) is one end point of focal chord of parabola y2=4ax, then other end point is(at2,−2at) (ii) Slope of line joining two points (x1,y1) and (x2,y2) is given by y2−y1x2−x1 If PQ is focal chord, then coordinates of Q will be (at2,−2at) Now, slope of QR =slope of PK 2ar+2atar2−at2=2atat2−2a⇒r+1tr2−1t2=tt2−2⇒1r−1t=1t2−2⇒r−1t=t2−2t=t−2t⇒r=t−1t=t2−1t