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Question

Let a red die, a blue die, a green die and a white die are rolled once, the dice being fair. The outcomes on the red, blue, green and white denote the numbers, a,b,c and d respectively. Let E denotes the event that absolute value of (a−1)(b−2)(c−3)(d−6)=1, then P(E) is:

A
1324
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B
1648
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C
2324
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D
1162
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Solution

The correct option is A 1324
Solution- Red die a
Blue die b
Green die c
White die d
(a1)(b2)(c3)(d4)=1
X Y W Z =1
Where X=a1,Y=b2,Z=c3,W=d6
{X,Y,Z,W} values for this,
Total ways {1,1,1,1}(d6) cannot be 1×{1,1,1,1}
{1,1,1,1}(d6) cannot be 1×{1,1,1,1}(d6) cannot be 1×{1,1,1,1}
{1,1,1,1}(d6) cannot be 1×{1,1,1,1}.
Total ways =4
Probability =46×6×6×6=23×2=1324
A is correct


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