Check Assignment of probability
Condition (i) : Each of the number p(ωi) is positive and less than one.
Condition (ii) : Sum of probabilities of each outcome of an event=1
(a) Each of the number p(ωi) is positive and less than one.
Sum of probabilities (SOP)=ω1+ω2+ω3+ω4+ω5+ω6
=16+16+16+16+16+16+16=66=1
Therefore, Assignment (a) is valid.
(b) Each of the number p(ωi) is either 0 or 1.
Sum of probabilities =(1+0+0+0+0+0+0=1)
Therefore, Assignment (b) is valid.
(c) Probability of any event cannot be negative.
(probability of events ω5 and ω6 are negetive)
Therefore, assignment (c) is not valid.
(d) Probability of any event cannot be greater than 1.
Since, p(ω6)=32>1
Therefore, assignment (d) is not valid.
(e) Sum of probabilities (SOP)
=ω1+ω2+ω3+ω4+ω5+ω6
=0.1+0.2+0.3+0.4+0.5+0.6=2.1
Since, sum of probabilities of events is greater than 1.
So, assignment (e) is not valid.