Let a sequence have 100 zeros to start with
In step 1: to every position in the sequence we add 1
In step 2: to every even position in the sequence we add 2
In step 3: to every position which is a multiple of 3, we add 3
Thus continues upto 100^th step. After the hundredth step, what will be the value of the 60^th position?

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Solution

Dear Student,

Multiples of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
For every multiple, 1 will be added to number at 60^th position which was initially 0.
So, there are 12 numbers for which 1 would be added.
So, number at 60^th position after 100 steps $1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 12$
Regards,

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Dear Student, Multiples of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60. For every multiple, 1 will be added to number at 60th position which was initially 0. So, there are 12 numbers for which 1 would be added. So, number at ​60th position after 100 steps 1+1+1+1+1+1+1+1+1+1+1+1=12 Regards,