Question

Let a sequence have 200 zeroes to start with. In step 1, to every position in the sequence we add 1. In step 2, to every even position in the sequence we add 1. In step 3, to every position which is a multiple of 3, we add 1. This is continued up to 200-th step. After the 200-th step, what will be the value in the 128th position?

• A. 8
• B. 16
• C. 128
• D. 200

Answer 1

The correct option is A 8

Since factor of 128 are $=1,2,4,8,16,32,64,128$
Hence it will be increased by 8.