A={1,2,3,4,5,6,7}
B={2,3,5,7}
C={2}
(A∩B)×C=(A×C)∩(B×C)
A∩B={1,2,3,4,5,6,7}∩{2,3,5,7}
={2,3,5,7}
(A∩B)×C={2,3,5,7}×{2}
={(2,2)(3,2)(5,2)(7,2)}….(1)
A×C={1,2,3,4,5,6,7}×{2}
={(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)(7,2)}
B×C={2,3,5,7}×{2}
={(2,2)(3,2)(5,2)(7,2)}
(A×C)∩(B×C)={(2,2)(3,2)(5,2)(7,2)}….(2)
From (1) and (2) we get
(A∩B)×C=(A×C)∩(B×C)