Let Aa- and Bb- be any two points in the space Rr- be a point on the line segment AB dividing it internally in the ratio m-n then r-

Let the unit vectors $\to a$ and $\to b$ are perpendicular and the unimodulus vector $\to c$ inclined at an angle $α$ to $\to a$ and $\to b$ . If $\to c = l \to a + m \to b + n (\to a \times \to b)$ , then

Q. Let

\to r

be a vector perpendicular to

\to a + \to b + \to c

, where

[\to a \to b \to c] = 2

. If

\to r = l (\to b \times \to c) + m (\to c \times \to a) + n (\to a \times \to b)

, then (l + m + n) is equal to

Q. If

\to r

be a vector perpendicular to

\to a + \to b + \to c

, where

[\to a \to b \to c] = z

and

\to r = ℓ (\to b \times \to c) + m (\to c \times \to a) + n (\to a \times \to b)

, then find

l + m + n

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Let A(→a) and B(→b) be any two points in the space R(→r) be a point on the line segment AB dividing it internally in the ratio m:n then →r=

The correct option is A m→b+n→am+nGiven r point divides AB line segment internally in ratio m:nThen →AR→RB=→m→nn→AR=m→RBn(→OR−→OA)=m(→OB−→OR)(m+n)→OR=m→OB+n→OA(m+n)→OR=m→b+n→a→OR=m→b+n→am+n

Let $A (\to a)$ and $B (\to b)$ be any two points in the space $R (\to r)$ be a point on the line segment AB dividing it internally in the ratio $m : n$ then $\to r$ =