Let A={x:−1≤x≤1} and f:A→A is a function defined by f(x)=x|x|, then f is
A
a bijection
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B
injection but not surjection
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C
Surjection but not injection
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D
neither injection nor surjection
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Solution
The correct option is Aa bijection The graph of f(x)=x|x|shows that it is a bijective function.
Since, distinct elements of the domain set mapping to the distinct elements in the codomain set. So, the function is one-one. And also every element of co-domain set has a pre-image element in domain, so the function is onto function also. Therefore, the given function is a bijective function.