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Question

Let A={x:1x1} and f:AA is a function defined by f(x)=x|x|, then f is


A
a bijection
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B
injection but not surjection
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C
Surjection but not injection
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D
neither injection nor surjection
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Solution

The correct option is A a bijection
The graph of f(x)=x|x|shows that it is a bijective function.

Since, distinct elements of the domain set mapping to the distinct elements in the codomain set.
So, the function is one-one.
And also every element of co-domain set has a pre-image element in domain, so the function is onto function also.
Therefore, the given function is a bijective function.


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