Given, A={x:x∈N}, B={x:x=2n,n∈N},
C={x:x=2n−1,n∈N}and
D={x:x is a prime natural number}.
So, A= set of natural numbers ={1,2,3,4,.....}
B= set of even natural numbers ={2,4,6,8,.....}
C= Set of odd natural numbers ={1,3,5,7,....}
D= set of all prime natural number ={1,2,3,5,7,11,.....}
Since, (A∩B). Therefore,
(A∩B)={1,2,3,4,....} ∩ {2,4,6,8,....}
(A∩B) ={2,4,6,8,.....}
Hence, (A∩B) ={2,4,6,8,....}=B.