The correct option is D Co domain of R−1 is {−3,−2,−1.0,1,2,3}
Here, A={x:x∈Z,|x|≤3}
|x|≤3
⇒−3≤x≤3
Since, x∈Z
A={−3,−2,−1,0,1,2,3}
B={y;y∈N,−1<y+2≤4}
−1<y+2≤4
⇒−3<y≤2
Since, y∈N
B={1,2}
Here, R is a relation from A to B
∴ Codomain of R is B={1,2}
Since Range of a relation is ⊂ of Co domain
Range ≠{0,1,2}
R−1 will be a relation from B to A
R−1⊂B×A
∴R−1 can be
{(1,1),(1,2),(1,3),(2,1),(2,2),(2,3)}
∴ Codomain of R−1 is A={−3,−2,−1,0,1,2,3}