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Question

Let A={x:xZ,|x|3} and B={y;yN,1<y+24}. If R be the relation from A to B, then

A
Co domain of R is {1,2}
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B
Range of R is {0,1,2}
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C
R1 can be {(1,1),(1,2),(1,3),(2,1),(2,2),(2,3)}
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D
Co domain of R1 is {3,2,1.0,1,2,3}
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Solution

The correct options are
A Co domain of R is {1,2}
C R1 can be {(1,1),(1,2),(1,3),(2,1),(2,2),(2,3)}
D Co domain of R1 is {3,2,1.0,1,2,3}
Here, A={x:xZ,|x|3}
|x|3
3x3
Since, xZ
A={3,2,1,0,1,2,3}

B={y;yN,1<y+24}
1<y+24
3<y2
Since, yN
B={1,2}

Here, R is a relation from A to B
Codomain of R is B={1,2}
Since Range of a relation is of Co domain
Range {0,1,2}

R1 will be a relation from B to A
R1B×A
R1 can be
{(1,1),(1,2),(1,3),(2,1),(2,2),(2,3)}
Codomain of R1 is A={3,2,1,0,1,2,3}



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