Let A - x - x - R - x -1- - B - x - x - R - x -1- - 1- and A - B - R - D- then the set D isA- - x - 1 - x -2-B- - x - 1- x - 2-C- - x - 1 - x - 2-D- None of these

The correct option is A [x:1≤ x2]A={x: x∈ R, |x| lt;1} B={x: x∈ R, |x 1|≥1} A∪ B=R D |x| lt;1⇒ 1 lt;x lt;1 ∴ A∈( 1, 1) |x 1|≥1⇒ (x 1)≥1 or (x 1)≤ ...

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Let A =[ x : ...

Question

Let $A = [x ∶ x \in R, | x | < 1];$ $B = [x ∶ x \in R, | x - 1 | \geq 1]$ and $A \cup B = R - D$ , then the set $D$ is

[x : 1 < x \leq 2]

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[x : 1 \leq x < 2]

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[x : 1 \leq x \leq 2]

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None of these

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Similar questions

Let A = { x : x ∈ R, |x| < 1}; B = {x : x ∈ R, |x-1| ≥ 1} and

A ∪ B = R - D, then the set D is

A = {x : x \in R, | x | < 1}

B = {x : x \in R, | x - 1 | \geq 1}

A \cup B = R - D

D

A = {x : - 1 < x < 1; x \in R}

B = {x : x \leq 0 or x \geq 2; x \in R}

A \cup B = R - C

C

Let $A = {x : x \in R, | x | < 1}$ ;
$B = {x : x \in R, | x - 1 | \geq 1}$ and

$A \cup B = R - D$ , then the set $D$ is

A = {x : x \in R, - 1 \leq x \leq 1}

B = {x : x \in R, | x | \leq 1}

A

B

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