Question

Let $A=\{x:x$ is a multiple of $3\}$ and $B=\{x:x$ is a multiple of $5\}$ then $A\cap B$ is given by

• A. $\{3,6,9,...\}$
• B. $\{5,10,15,20,...\}$
• C. $\{15,30,45,...\}$
• D. None of these

Answer 1

The correct option is C $\{15,30,45,...\}$

Hence

$A\cap B$ will be a multiple of $15$.

$=\{15,30,45,\mathrm{60...}\}$

Hence, option 'C' is correct.