Let A = {x, y, z} and B = {a, b}. Find the total number of relations from A into B.
We have,
A = {x, y, z} and B = {a, b}
⇒n(A)=3 and n(B) = 2
⇒n(A)×n(B)=3×2=6
⇒n(A×B)=6
[∵n(A×B)=n(A)×n(B)]
So, there are 26=64 relations from A to B.
[∵n(x)=a,n(y)=b⇒Total number of relations=2ab]