Let AB be a chord of the circle x2+y2=r2 subtending a right angle at the centre. Then the centroid of the triangle PAB as P moves on the circle is
AB = a is any chord
C(h,k) is the midpoint of AB
⟹AC=BC=a2
Given ∠AOB=90
⟹AB2=OA2+OB2
⟹a2=r2+r2=2r2
In △OBC
OC⊥BC
⟹OC2=OB2−BC2
(h−0)2+(k−0)2=r2–(a2)2
h2+k2=r−r22=r22
Locus of above equation is
x2+y2=(r√2)2 which is a circle