Let AB be a chord of the parabola y2=4ax.If the pole of AB with respect to the parabola be (2a,3a) then the length of AB is
A
√13a
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B
4a
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C
5a
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D
2√3a
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Solution
The correct option is B√13a Given pole of AB w.r.t the parabola y2=4ax is (2a,3a) Thus the equation of chord AB is given by T=0 ⇒y(2a)−2a(x+3a)=0 ⇒y=23x+43a Clearly here m=23,c=43a Therefore length of chord AB is =4m2√a(1+m2)(a−cm)=√13a