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Question

Let abc be a three digit number. Then abc-cba is not divisible by


A

9

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B

11

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C

18

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D

33

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Solution

The correct option is C

18


Explanation for the correct option:

Expanding form of number:

The general form of given numbers is as follows,

abc=100a+10b+ccba=100c+10b+a

Now,

abc-cba=100a+10b+c-100c-10b-aabc-cba=99a-99cabc-cba=99(a-c)abc-cba=(3×3×11)(a-c)

abc-cba is divisible by 99 and its factors, 3,9,11 and 33 . It is also divisible by (a-c).

Hence, option(C) is correct.


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