Relationship between Unequal Sides of Triangle and the Angles Opposite to It.
Let ABC be a ...
Question
Let ABC be a triangle and →a, →b and →c be the position vectors of the point. A,Band C, respectively. External bisectors of ∠B and\angleCmeetatPwiththesidesofthetriangleas\vec a, \vec b and\vec cthepositionvectorsofP$ becomes
A
(−b)b+(−c)c(b+c)
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B
aa+(−b)b+(−c)c(a−b−c)
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C
(a+b+c3)(abc)
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D
aa+bb+cc(a+b+c)
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Solution
The correct option is Caa+(−b)b+(−c)c(a−b−c)
Vectors along AB, BC and CA are b - c, c - b and a - c, respectively. Hence, the bisectors of the angular B and C, respectively are