Let ABC be a triangle such that ∠ACB=π6 and let a,b and c denote the lengths of the sides opposite to A,B and C respectively. The value(s) of x for which a=x2+x+1,b=x2−1 and c=2x+1 is (are)
A
−(2+√3)
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B
1+√3
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C
2+√3
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D
4√3
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Solution
The correct option is B1+√3 Using cosine rule for ∠C