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Question

Let ABC be a triangle whose circumcentre is at P. If the position vectors of A,B,C and P are a,b,c and a+b+c4 respectively, then the position vector of the orthocentre of this triangle, is:

A
(a+b+c2)
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B
a+b+c
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C
(a+b+c)2
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D
0
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Solution

The correct option is B (a+b+c)2
O is orthocentre and G is centroid and C is circumcentre. G divides OC in 2:1 ratio.
Position vector of centriod G=a+b+c3
Position vector of circum center C=a+b+c4
Apply Section Formula,
G=2C+R3
3G=2C+R
R=3G2C=(a+b+c)2(a+b+c4)
=a+b+c2
509714_474802_ans.jpg

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