Let ABC be a triangle whose circumcentre is at P- If the position vectors of A- B- C and P are a- b- c- and a- - b- - c-4 respectively- then the position vector of the orthocentre of this triangle- is-

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Section Formula

Let ABC be ...

Question

Let $A B C$ be a triangle whose circumcentre is at P. If the position vectors of $A, B, C$ and P are $\to a, \to b, \to c$ and $\frac{\to a + \to b + \to c}{4}$ respectively, then the position vector of the orthocentre of this triangle, is:

- (\frac{\to a + \to b + \to c}{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to a + \to b + \to c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{(\to a + \to b + \to c)}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\to 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

A B C

P

A, B, C

P

\to a, \to b, \to c

\frac{\to a + \to b + \to c}{4}

\to a, \to b, \to c

x y z

\to a \times \to b = \to b \times \to c = \to c \times \to a \neq \to 0

A, B, C

\to a, \to b, \to c

A B C

\to a, \to b, \to c

A, B, C

Δ A B C

\to r

P

(| \to b - \to c | + | \to c - \to a | + | \to a - \to b |) \to r = | \to b - \to c | \to a + | \to c - \to a | \to b + ∣ ∣ \to a - \to b ∣ ∣ \to c

P

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

| \to a \times \to b | + | \to b \times \to c | + | \to c \times \to a | =

Join BYJU'S Learning Program