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Question

Let ABC be an acute scalene triangle, and O and H be its circumcentre and orthocentre respectively. Further let N be the midpoint of OH. The value of the vector sum NA+NB+NC is

A
0 (zero vector)
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B
HO
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C
12HO
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D
12OH
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Solution

The correct option is B 12HO
HE=NENH
12AH=12[NB+NC]12OH ....(HEBC,AHBC)
HEAH
HE=Rcos(A),AH=2Rcos(A)HE=12AH
E midpoint of BC
NE=12[NB+NC]
N midpoint of OH
NH=12OHNHNA=NB+NC+OH
NA+NB+NC= -OH+12OH
= 12HO

1324119_739183_ans_bd2f632d284a4abca6070849f98e8eca.jpg

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