Let ABC be an equilateral triangle inscribed in the auxiliary circle of the ellipse x2a2+y2b2=1,(a>b).A′B′C′ be corresponding triangle inscribed within the ellipse , then centroid of the trianlgle A′B′C′ lies at:
A
focus of ellipse
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B
any vertex of the ellipse
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C
centre of the ellipse
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D
none
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Solution
The correct option is C centre of the ellipse for, x2a2+y2b2=1(a>b)