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Standard XII

Physics

Principle of Superposition

Let ABC is a ...

Question

Let ABC is a right angled triangle in which AB = 3 cm and BC = 4 cm and $∠ A B C = 90^{o}$ . The three charges +15, +12 and -20 esu are placed on A, B and C respectively. The force acting on B will be

Zero

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25 dyne

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30 dyne

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150 dyne

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Solution

The correct option is A 25 dyne
The given condition ca be shown as below
Net force on $B, F_{n e t} = \sqrt{F_{A}^{2} + F_{C}^{2}}$
$∴ F_{A} = \frac{5 \times 12}{(3)^{2}} = 20 d y n e$
and $F_{C} = \frac{12 \times 20}{(4)^{2}} = 15 d y n e$
So, $F_{n e t} = \sqrt{(20)^{2} + (15)^{2}} = 25 d y n e .$

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Let ABC is a right angled triangle in which AB = 3 cm and BC = 4 cm and ∠ABC=90o. The three charges +15, +12 and -20 esu are placed on A, B and C respectively. The force acting on B will be

The correct option is A 25 dyneThe given condition ca be shown as belowNet force on B,Fnet=√F2A+F2C∴FA=5×12(3)2=20dyneand FC=12×20(4)2=15dyneSo, Fnet=√(20)2+(15)2=25dyne.

Let ABC is a right angled triangle in which AB = 3 cm and BC = 4 cm and $∠ A B C = 90^{o}$ . The three charges +15, +12 and -20 esu are placed on A, B and C respectively. The force acting on B will be